Question

find the simple interest and the amount payable on a loan of rupees 15000 at 8% per annum for 4 years

Answer 1

Solutions :-

Given :

Principle (p) = Rs 15000
Time (t) = 4 years
Rate (r) = 8% p.a.

Find the Simple Interest (S.I) :-

$S.I = \frac{p \times r \times t}{100} \\ \\ \\=Rs \: (\frac{15000 \times 8 \times \times 4}{100} ) \\ \\ = \: Rs \: (\frac{480000}{100}) = Rs \: 4800$

Now,
Find the Amount (A) :-

$A = S.I \: + p \\ \\ = Rs \: (4800 + 15000) \\ \\ = Rs \: 19800$

Hence,
The simple interest is Rs 4800
And the amount is Rs 19800

Answer 2

HEY MATE HERE IS YOUR ANSWER
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|Given : |
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Principal :- ₹ 15000
Time :- 4 years
Rate :- 8%
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| To Find :- |
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Simple interest

By using :⬇️

S. I = p × r × t / 100

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| Solution :- |
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S. I = 15000 × 8 × 4 /100

S. I = 480000 / 100
S. I = 4800 ₹



Now,

To find amount

A = S. I + P
A = 4800 + 15000
A = 19800 ₹


Answers we find from above solutions are :⬇️

Simple interest :- 4800 ₹
Amount :- 19800 ₹

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HOPE IT WILL HELP YOU

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