Question

Find the simple interest for Rs 4500 for 2 years at the rate of 11% per annum.

Answer 1

Here is your answer..................
P- Rs 4500
T-2 year
R-11%p.a.
S.I =
PxRxT÷100
= 4500x2x11÷100
=990
:::::::::::::::::::;hope it help you :::::::::::::::::::::::::::

Answer 2

Given,

Rs 4500 for 2 years at the rate of 11% per annum.

To Find,

The simple interest =?

Solution,

We can solve the question as follows:

It is given that we have to find the simple interest on Rs. 4500 for 2 years at the rate of 11% per annum.

$Principal\: amount = Rs.\: 4500$

$Time = 2\: years$

$Rate = 11$%

The formula for simple interest is given as:

$Simple\: interest = \frac{PRT}{100}$

Where,

$P = Principal\: amount$

$R = Interest\: rate$

$T = Time$

To find the simple interest, we will substitute the given values in the above formula.

$Simple\: interest = \frac{4500*11*2}{100}$

                         $=45*11*2$

                         $= Rs.\: 990$

Hence, the simple interest is equal to Rs. 990.