Question

Find the simple interest on:
(1) rupees. 350 for 2 years at 11% per annum .
(ii) rupees.20000 for 4 1/2 years at 8 1/2% per annum .
(iii) rupees.648 for 8 months at 16 2/3% per annum.
Also find the amount in each case.​

Answer 1

Answer:

$si = \frac{p \times r \times t}{100} \\ 1) = \frac{350 \times 2 \times 11}{100} \\ 7 \times 11 = 77$

$20000 \times \frac{9}{2} \times \frac{17}{2} \times \frac{1}{100} \\ 200 \times \frac{9}{2} \times \frac{17}{2} \\ 50 \times 9 \times 17 = 7650$

3 )

$648 \times \frac{8}{12} \times \frac{50}{3} \times \frac{1}{100} \\ \frac{648}{9} = 72$

so amount will be

so amount will be 1 no. = 350 + 77 = 427

2 no. = 20000 + 7650 = 27650

3 no. = 648 + 72 = 720

HOPE THIS HELPS YOU OUT

MARK AS BRAINLIEST