Question

find the simple interest on ₹112.50 for 4 years at 3/2 % per annum.​

Answer 1

Step-by-step explanation:

here is the answer of your question hope it's helpful for you

Answer 2

Now according to the question-

Now according to the question-100P×8×3=100P×9×2+96

Now according to the question-100P×8×3=100P×9×2+96⇒100P×24=100(P×18)+9600

Now according to the question-100P×8×3=100P×9×2+96⇒100P×24=100(P×18)+9600⇒24P=18P=9600

Now according to the question-100P×8×3=100P×9×2+96⇒100P×24=100(P×18)+9600⇒24P=18P=9600⇒24P−18P=9600

Now according to the question-100P×8×3=100P×9×2+96⇒100P×24=100(P×18)+9600⇒24P=18P=9600⇒24P−18P=9600⇒P=69600=1600

Now according to the question-100P×8×3=100P×9×2+96⇒100P×24=100(P×18)+9600⇒24P=18P=9600⇒24P−18P=9600⇒P=69600=1600Hence the sum is Rs.1600.

Now according to the question-100P×8×3=100P×9×2+96⇒100P×24=100(P×18)+9600⇒24P=18P=9600⇒24P−18P=9600⇒P=69600=1600Hence the sum is Rs.1600.Hence the correct answer is 1600.