Question

Find the simple interest on 2,000 for six months at the rate of 4¹2% per annum​

Answer 1

Answer:

answer

Step-by-step explanation:

Principal (P) = Rs 2000

Rate of Interest (R) = 4 whole \frac{1}{2}

2

1

% per annum = 4.5 % p.a

Time (T) = 6 months = \frac{6}{12}

12

6

years = \frac{1}{2}

2

1

years = 0.5 years

To be found :-

The Simple Interest (S.I)

S.I = \frac{P \times R \times T }{100}

100

P×R×T

S.I = \frac{2000 \times 4.5 \times 0.5}{100}

100

2000×4.5×0.5

S.I = Rs 45

mark my answer as brainliast if it helps you

Answer 2

Anser :420 Rs

step by step explanation:

formula for simple interest =[P×R×N]/2

now 6 months =1/2 year

2000×0.42×0.5=420

final amount =P×(1+r×t)

2000×(1+0.42×0.5)

2000×1.21

2420

2420-2000=420