Math, asked by ishaannaik2007, 4 months ago

find the simple interest on ₹5000 for 2 1/2 year at a rate of 7 2/3% pa​

Answers

Answered by NewtonofINDIA
0

si = 50 X 23/3 X 2.5 = 960 rs. approx

pls mark as brainliest

Answered by BrainlyTopper97
77

{\large{\boxed{\underline{\mathrm{\bf{\orange{Given:-}}}}}}}

  • Principal = ₹5,000
  • Time = {\mathsf{2\dfrac{1}{2} \ years}}
  • Rate of Interest = {\mathsf{7\dfrac{2}{3}\%}}

{\large{\boxed{\underline{\mathrm{\bf{\red{To \ Find:-}}}}}}}

  • Simple Interest

{\large{\boxed{\underline{\mathrm{\bf{\pink{Formula \ Used:-}}}}}}}

{\pink{\bigstar}} \ {\boxed{\tt{\green{S.I. = \dfrac{P \times R \times T}{100}}}}} \ {\pink{\bigstar}}

Where,

  • S.I. = Simple Interest
  • P = Principal i.e. ₹5,000
  • R = Rate of Interest i.e. {\mathsf{7\dfrac{2}{3}\%}}
  • T = Time i.e. {\mathsf{7\dfrac{2}{3}\%}}

{\large{\boxed{\underline{\mathrm{\bf{\blue{Solution:-}}}}}}}

  • Principal = ₹5,000
  • Time = {\mathsf{2\dfrac{1}{2} \ years}}
  • Rate of Interest = {\mathsf{7\dfrac{2}{3}\%}}

______________________________

{\mathsf{2\dfrac{1}{2} \ years = \dfrac{5}{2} \ years}}

{\mathsf{7\dfrac{2}{3}\% = \dfrac{23}{3}\%}}

______________________________

According to the question by using the formula of Simple Interest, we get,

\longmapsto {\mathsf{S.I. = \dfrac{5,000 \times 23 \times 5}{100 \times 3 \times 2}}}

\longmapsto {\mathsf{S.I. = \dfrac{50 \times 23 \times 5}{3 \times 2}}}

\longmapsto {\mathsf{S.I. = \dfrac{5750}{6}}}

\longmapsto {\mathsf{S.I. =958.{\overline{33}}}}

{\orange{\bigstar}} \ \therefore {\boxed{\underline{\mathsf{\green{Simple \ Interest}{\red{ \ is \ }{\blue{\bf{Rs. 958.{\overline{33}}}}}}}}}} \ {\orange{\bigstar}}

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