Find the simple interest on a loan of Rs 15,000 at 8% p.a. for 4 years.
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Answer:
Solutions :-
Given :
Principle (p) = Rs 15000
Time (t) = 4 years
Rate (r) = 8% p.a.
Find the Simple Interest (S.I) :-
\begin{gathered} S.I = \frac{p \times r \times t}{100} \\ \\ \\=Rs \: (\frac{15000 \times 8 \times \times 4}{100} ) \\ \\ = \: Rs \: (\frac{480000}{100}) = Rs \: 4800 \end{gathered}
S.I=
100
p×r×t
=Rs(
100
15000×8××4
)
=Rs(
100
480000
)=Rs4800
Now,
Find the Amount (A) :-
\begin{gathered} A = S.I \: + p \\ \\ = Rs \: (4800 + 15000) \\ \\ = Rs \: 19800 \end{gathered}
A=S.I+p
=Rs(4800+15000)
=Rs19800
Hence,
The simple interest is Rs 4800
And the amount is Rs 19800
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