Question

Find the simple interest on rupees 500 for 3 years at the rate of 10% per annum?

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Simple\:Interest=150\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Principal(p) = 500 \: rupees\\ \\ \tt: \implies Time(t) = 3 \: years \\ \\ \tt: \implies Rate\%(r)= 10\% \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Simple \: Interest(S.I) = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies S.I= \frac{p \times r \times t}{100} \\ \\ \tt: \implies S.I= \frac{500 \times 10 \times 3}{100} \\ \\ \tt: \implies S.I = 5 \times 10 \times 3 \\ \\ \green{\tt:\implies S.I = 150 \: rupees} \\ \\ \bold{As \: we \: know \:that} \\ \tt: \implies A= p + S.I \\ \\ \tt: \implies A = 500 + 150 \\ \\ \green{\tt: \implies A = 650 \: rupees}\\ \purple{\tt{Some \: formula \: related \: to \: topic}} \\ \pink{\circ \: \tt A = p(1 + \frac{r}{100})^{t} } \\ \\ \pink{\circ \: \tt C.I= A - p }$

Answer 2

AnswEr :

Rs.150.

$\bf{\green{\underline{\underline{\bf{Given\::}}}}}$

• Principal, (P) = Rs.500
• Rate, (R) = 10%
• Time, (T) = 3 years.

$\bf{\green{\underline{\underline{\bf{To\:find\::}}}}}$

The simple Interest (S.I.).

$\bf{\green{\underline{\underline{\bf{Explanation\::}}}}}$

Formula use :

$\bf{\boxed{\bf{Simple\:Interest\:(S.I.)=\frac{P\times R\times T}{100} }}}}}$

$\bf{\red{\underline{\underline{\tt{A.T.Q\::}}}}}$

$\dashrightarrow\tt{S.I.=\dfrac{P*R*T}{100} }\\\\\\\dashrightarrow\tt{S.I.=\dfrac{5\cancel{00}*10*3}{\cancel{100}} }\\\\\\\dashrightarrow\tt{S.I.=Rs.\big(5\times 10\times 3\big)}\\\\\\\dashrightarrow\tt{\red{S.I.=Rs.150}}$

Thus,

$\therefore\sf{\large{\pink{\underline{\sf{The\:simple\:Interest\:(S.I.)=Rs.150}}}}}$