find the size, nature and position of image formed when an object of size 1cm is placed at a distance of a distance of 15 cm from a concave mirror of focal length 10 cm
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Answered by
4
here
u=-15cm
f=-10cm
h1=1cm..
using 1/u+1/v=1/f
1/v=1/f-1/u
=-1/10+1/15
v= -30cm
h2/h1=-v/u
h2= -2cm
u=-15cm
f=-10cm
h1=1cm..
using 1/u+1/v=1/f
1/v=1/f-1/u
=-1/10+1/15
v= -30cm
h2/h1=-v/u
h2= -2cm
kvnmurty:
nature of the image? ?
nature of image will be inverted and its size will be 2 cm
Answered by
2
1/f=1/v +1/u
-1/10=1/v -1/15
-1/10+1/15=1/v
-1/30 = 1/v
v=30cm from the optical centre
image will lie beyond C
-1/10=1/v -1/15
-1/10+1/15=1/v
-1/30 = 1/v
v=30cm from the optical centre
image will lie beyond C
nAture and size of images???
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