If KE body is increased by 100% . Then % change in 'P'
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KE = 1 /2 m v² = p²/(2m)
Assuming the body has the same mass,
if KE becomes twice (as it increases by 100%), then p becomes √2 times.
So p becomes 1.414 times its previous value.
So it increases by 0.414 * 100 = 41.4%
Assuming the body has the same mass,
if KE becomes twice (as it increases by 100%), then p becomes √2 times.
So p becomes 1.414 times its previous value.
So it increases by 0.414 * 100 = 41.4%
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