Question

Find the size, nature and position of image formed when an object of size 1cm is placed at a distance of 15cm from a concave mirror of focal length 10cm.

Answer 1

hø=1,v=15,f=-10 (focal length of conacave mirror is -ve)

u=? hî=?

then,

u=v×f/(v-f)

u=15×-10/15-(-10)

u=-150/25

u=-6

hî=-(v/u)×hø

$1 \times \frac{ - 15}{ - 6}$

hî=15/6




virtual image

Answer 2

$\textbf{Answer is in Attachment !}$