Question

find the size , nature and position of the image formed when an object of size 5 cm is placed at distance of 15 cm from a concave mirror of focal length 10 centimetre

Answer 1

ho=5cm. u= -15cm. f= -10cm. v=?
1/v. =. 1/f - 1/u.
1/v = -1/10 - (-1/15)
1/v = -3+2/30
1/v = -1/30
v = -30cm
image - real , inverted
magnification= -v/u
-(-30/-15)
-2
image formed real inverted twice the size of object