find the size of the angles of a parallelogram if one angle is 20 less than twice the smallest angle
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Answer:
Step-by-step explanation:
let smallest angle be x°
then the other will be (2x-20)°
we know that adjacent angles of ||gm are supplementary
therefore,
x + 2x-20=180
3x=180+20
3x=200
x=200/3
x=66.6°
other angle =2× 66.6. -20= 113.3°
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