Question

Find the sizes of the angle of parallelogram if one angle is 20°less than twice the smallest angle

Answer 1

Answer:

X+(X+20)=180

2x+20=180

2x = 180-20=160

X=160÷2

X= 80

so the angles are 80 and 100

Answer 2

Answer:

Let smallest angle be x

stp1 : the size of one angle is 20° less than twice of small angles

stp2 : Therefore = x+x+(2x-20° )

stp3 : x+x+(2x-20°) = 360°

stp4 : 4x-20°=360°

stp5 : 4x= 360°+20°

stp5 : 4x= 380°

stp6 : x= 380°/4

stp7 : x=95°

So th smallest angle is 95°

cheak : 95+95+(2×95-20) =360°

190(190-20)=360°

190+ 170=360°

360° = 360°

LHS = RHS