Find the sizes of the angles of a parallelogram if one angle is 20° less than twice the smallest angle.
Answers
Answered by
603
let smallest angle be x°
then the other will be (2x-20)°
we know that adjacent angles of ||gm are supplementary
therefore,
x + 2x-20=180
3x=180+20
3x=200
x=200/3
x=66.6°
other angle =2× 66.6. -20= 113.3°
then the other will be (2x-20)°
we know that adjacent angles of ||gm are supplementary
therefore,
x + 2x-20=180
3x=180+20
3x=200
x=200/3
x=66.6°
other angle =2× 66.6. -20= 113.3°
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Answered by
152
let one pair if opposite angle measure x and another as y
.let y be smallest
therefore x=2y-20
and x+y=180 (in parallelogram sum of adjacent angles is 180)
2y-20+y=180
3y=200
y=66.66
.let y be smallest
therefore x=2y-20
and x+y=180 (in parallelogram sum of adjacent angles is 180)
2y-20+y=180
3y=200
y=66.66
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