Find the sizes of the angles of a parallelogram if one angle 20 less than twice the smallest angle.
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Suppose angle 1 = x
And angle 2 = 2x-20
Therefore,
x + 2x - 20 = 180
3x = 180 + 20
3x = 200
x = 66.66
Approximately x = 66.7
2x - 20
2(66.66) - 20
133.32 - 20
113.32
The required angle 1 is 66.7 and angle 2 is 113.3 ......... Approximately
And angle 2 = 2x-20
Therefore,
x + 2x - 20 = 180
3x = 180 + 20
3x = 200
x = 66.66
Approximately x = 66.7
2x - 20
2(66.66) - 20
133.32 - 20
113.32
The required angle 1 is 66.7 and angle 2 is 113.3 ......... Approximately
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