Question

find the slope of a line parallel to the line which passes through the points (-5,-8) and (3,0)

Answer 1

The slope of line parallel to the line joining the points (-5,-8) & (3,0) is ;

m = (y2-y1)/(x2-x1)
= [3-(-5)]/[0-(-8)]
= (3+5)/(0+8)
= 8/8
= 1

m = 1

Answer 2

slope of that line is same as the slope of AB where A=(-5,-8) & B=(3,0)

slope = (y₂ - y₁) / (x₂ - x₁)
          = (0 - (-8) ) / (3 - (-5) )
          = 8/8 = 1

slope = 1,  this line is parallel to  y = x.