Question

find the slope of a line perpendicular to another line joining the points (-5,3) and (2,6)

Answer 1

Answer:

- 7 / 3

Step-by-step explanation:

Given to find the slope of a line perpendicular to another line joining the points (-5,3) and (2,6)

Let AB be a line. Let CD be perpendicular to AB. The two points will be A(-5,3) and B(2,6)

The product of the slope is equal to -1, if two lines are perpendicular.

Sp slope of AB x slope of CD = -1

Now slope joining two points is given by y2 - y1 / x2 - x1

  Slope AB = 6 -3 / 2 - (- 5) = 3 / 7

Given Slope AB x CD = - 1

           3/7 x CD = - 1

           CD = - 1 / 3 / 7 = - 7 / 3

Slope of CD = - 7/3

Answer 2

first of all, you should find out slope of line joining the points (-5,3) and (2,6).

we know, slope of line joining two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,$m=\frac{y_2-y_1}{x_2-x_1}$

so, slope of line joining the points (-5,3) and (2,6) = (6 - 3)/{2 - (-5)} = 3/7

now, find slope of required line .
a/c to question,
required line is perpendicular to line joining the points (-5,3) and (2,6).
So, slope of required line × slope of line joining the points (-5,3) and (2,6) = -1

or, slope of required line × (3/7) = -1

hence,slope of required line = -7/3