find the slope of a line which is prependicular to the line y=5x+3
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product of slope of perdendicular lines is - 1
there for slope of line perpendicular to given line is -1/5
there for slope of line perpendicular to given line is -1/5
Devashish2000:
how u get the product -1
its a property
can u tell me dude
ok intersting lines for a pair of straight lines
if angle between them is 90 ... multiply eq of both lines u ll get a joint eq of posl
now if u divied whole eq my x² u ll get a quadratic in m (slope)
This has a big answer which is done by the calucalating the tan(angle between lines whose slopes are m1,m2).....then taking the taking the denominator 0 as tan(90) tends to infinity.....as in the denominator is m1m2+1....that implies m1m2= -1.....now you may ask how to calculate the tangent of the formed angle this is better if you ask in google....or see any joint level or cbse level coordinate geometry or ask google
and product of roots of that quadratic will always be - 1
thank u juststudent1411 and rahul 10001000
Answered by
1
the slope of this line is 5....now let the slope of the line perpendicular to this line be m
now 5m = -1 for they to be perpendicular
that means m= -0.2 or -1/5
now 5m = -1 for they to be perpendicular
that means m= -0.2 or -1/5
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