find THE SLOPE OF STRAIGht line
3х +4y+8=0
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3x+4y+8=0……………….(1)
or. 4y=-3x-8
or. y = (-3/4).x - 2. , by comparing with standard form. y=m1.x+c
m1=-3/4.
Let slope of a line which is perpendicular to (1). is .m2.
m1×m2. = -1.
(-3/4). × m2= -1
m2= 4/3. Answer.
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