Find the slope of tangent to the curve y = 2x¹-x² +3 at (1/2,2)
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2
+3sinx
dx
dy
=4x+3cosx
(
dx
dy
)
(0,0)
=4×0+3cos0=3
So, the equation of the normal at (0,0) is :
y−0=−
3
1
(x−0)
x+3y=0
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