Find the slope of tangent to the curve
y = x^3-3x^2-9x+5
Answers
Answered by
1
Answer:
Given, y=x
3
−3x
2
−9x+5
⇒
dx
dy
=3x
2
−6x−9
We know that, this equation gives the slope of the tangent to the curve. The tangent is parallel to x-axis,
∴
dx
dy
=0
⇒3x
2
−6x−9=0
⇒x=−1,3
Similar questions