Math, asked by nalawadekartik13, 6 months ago


Find the slope of tangent to the curve
y = x^3-3x^2-9x+5​

Answers

Answered by rakeshkushwaha379057
1

Answer:

Given, y=x

3

−3x

2

−9x+5

dx

dy

=3x

2

−6x−9

We know that, this equation gives the slope of the tangent to the curve. The tangent is parallel to x-axis,

dx

dy

=0

⇒3x

2

−6x−9=0

⇒x=−1,3

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