Question

Find the slope of the curve y=[(4-x)^2]/x at point 2,2​

Answer 1

Answer:

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It is given that

y = \frac{4}{x}y=

x

4

Differentiating both sides with respect to x we get

\frac{dy}{dx} = - \frac{4}{ {x}^{2} }

dx

dy

=−

x

2

4

So the required slope is =- \frac{4}{ {2}^{2} } = - \frac{4}{4} = - 1−

2

2

4

=−

4

4

=−1

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