Question

Find the slope of the diagonals of a quadrilateral with vertices A(1,7), B(6,3), C(0,-3) and D(-3,3).

Answer 1

Final Answer : 10, 0

Logic Used :
1# Slope = (y(2)-y(1)) /(x(2)-x(1))
where,x,y these are respective co-ordinates of points on line.

Steps:
1) Diagonals are : AC & BD
We have,
A = (1,7) : B = (6,3) : C = (0,-3) : D = (-3,3)

Slope of AC :
$\frac{(7) - ( - 3)}{ 1 - 0} = 10$
Slope of BD :
$\frac{3 - 3}{6 - ( - 3)} = 0$

Hence, we got required slopes as 10 & 0.