Question

find the slope of the line joining the points (2a,-3b) and (-2b,3a)​

Answer 1

Answer:

this is the answer of your questions

Answer 2

$Let \: A(2a,-3b) \:and \: B(-2b , 3a )$

$Slope \: of \:the \: line \: passing \: through \\A(2a,-3b) \:and \: B(-2b,3a)$

$Here, x_{1} = 2a, y_{1} = -3b \\and \: x_{2} = -2b, y_{2} = 3a$

$\pink {Slope \:of \: \overline{AB}} \\\pink {= \frac{y_{2} - y_{1}}{x_{2} - x_{1}}} \\= \frac{3a-(-3b)}{-2b-2a} \\= \frac{3a + 3b}{-2b-2a} \\= \frac{3(a+b)}{(-2)(a+b)} \\= \frac{-3}{2}$

Therefore.,

$\red{ Slope \: of \:the \: line \: passing} \\\red{ through \:A(2a,-3b) \:and \: B(-2b,3a)}\\\green {= \frac{-3}{2}}$

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