Question

find the slope of the line joining the two given points A(3,-2)B(-6,-2). Don't spam I will report u​

Answer 1

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Answer 2

Answer:

┌⋆Solution⋆┐

\begin{gathered}Slope \: of \: AB = \frac{y_2-y_1}{x_2-x_1}\\\therefore Points \:to \:be \:consider \\\implies A(3,-2)\\\implies B(-6,-2)\\\ means \: , x_1 = 3 ,/: x_2 = -6 \\ y_1 = -2 ,\: y_2 = -2 \\\\ Now,slope\: of \: AB = \frac{-2-(-2)}{-6-(3)}\\\implies \frac{-2+2}{-9} \\\implies 0\end{gathered}

SlopeofAB=

x

2

−x

1

y

2

−y

1

∴Pointstobeconsider

⟹A(3,−2)

⟹B(−6,−2)

means,x

1

=3,/:x

2

=−6

y

1

=−2,y

2

=−2

Now,slopeofAB=

−6−(3)

−2−(−2)

⟹

−9

−2+2

⟹0

\red{\underline{Answer}}

Answer

Slope \: of \: AB = 0SlopeofAB=0

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