Question

Find the slope of the line joining the two given points A(3, −2), B(−6, −2)

Answer 1

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$Slope \: of \: AB = \frac{y_2-y_1}{x_2-x_1}\\\therefore Points \:to \:be \:consider \\\implies A(3,-2)\\\implies B(-6,-2)\\\ means \: , x_1 = 3 ,/: x_2 = -6 \\ y_1 = -2 ,\: y_2 = -2 \\\\ Now,slope\: of \: AB = \frac{-2-(-2)}{-6-(3)}\\\implies \frac{-2+2}{-9} \\\implies 0$

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$Slope \: of \: AB = 0$

Answer 2

Hello!

Explanation:

Slope: $\frac{Y^2-Y^1}{X^2-X^1}=\frac{rise}{run}$

$\frac{(-2)-(-2)=-2+2=0}{(-6)-3=-9}=\frac{0}{9}=\frac{0/0}{9/0}=0$

Answer: 0.

Slope is 0.

Hope this helps!

-Charlie