Question

find the slope of the line which is parallel and perpendicular 3x + 4y - 1=0​

Answer 1

Answer:

Any line perpendicular to the line 3x+4y-1=0 is of the form 4x-3y+k=0. If this passes through (1,2) then 4–6+k=0 or k=2. Hence the equation of the perpendicular line is 4x-3y+2=0. The point of intersection is got by solving the two equations. We get x= 3/5 and y=-1/5. These are the coordinates of the point of intersection of the two lines.

Answer 2

From the equation

3x + 4y - 1 = 0

4y = -3x + 1

y = (-3/4)x + 1/4

By comparing with the equation of a straight line

y = mx + c

m = -3/4

For parallel

m2 = m1

m2 = -3/4

For perpendicular

m2 = -1/m1

m2 = -1/(-3/4)

m2 = 4/3