Question

find the slope of the polar of (1,3)with respect to the circle x^2+y^2-4x-4y-4=0.also find the distance from the centre of it​

Answer 1

Answer:

Now equation of the circle will be x^2 + y^2 – 4x – 4y – 4 = 0, centre C = (2,2)

Now given Polar of (1,3) is 0

Now the equation will be  

So xx1 + yy1 – 4(x1 + x2 / 2) – 4(y1 + y2 / 2) – 4 = 0

So x x 1 + y x 3 – 2(x + 1) – 2(y + 3) – 4 = 0

So x + 3y – 2x – 2 – 2y – 6 – 4 = 0

So – x + y – 12 = 0

Or x – y + 12 = 0

Now distance from the centre will be  

C(2,2) = l – 2 + 2 – 12 / √1 + 1  l

         = 12 / √2

           = 3 √2

Answer 2

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