Find the slope of the tangent at the origin to the curve
Y ( x^2 + 1 ) = x.
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Answer:
y=+-x
Step-by-step explanation:
y=+
−
x
2
+x
3
y
′
=+
−
2
x
2
+x
3
2x+3x
2
y
′
=+
−
2
1+x
2+3x
y
′
∣
x=0
=+
−
1
y=+
−
x
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