find the slope of the tangent to the curve at given point Y=3x^2-4 at(1,-1)
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The given curve is y=3x4−4x.
Thus, the slope of the tangent to the given curve at x=4 is given by,
[dxdy]x=4=[12x3−4]x=4=12(4)3−4=12(64)−4=764
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