Question

Find the slope of the tangent to the curve y= x cube -2x+1 at the point x=2

Answer 1

Equation of curve:-

y=x³-2x+1

Taking derivative,

dy/dx= 3x²-2

[dy/dx]ₓ₋₂= 3*2²-2= 12-2= 10

Thus slope= 10