Question

Find the sum which amounts to rs 1352 in 2 years at 4% compound interest

Answer 1

Answer:

Step-by-step explanation:

Amount (A) = 1352 RS

Time(n) = 2 years

Rate = 4%

Amount = P ( 1+\frac{r}{100} )^{n}

1352 = P (1+ \frac{4}{100}) ^{2}

1352 = P (1+\frac{1}{25} )^{2}

1352 = P (\frac{26}{25} )^{2}

P= 1352×25× 25/26×26

p= 845000/676

P= 1250 RS

Answer 2

Given :-

• Amount (A) = Rs.1352

• Time (n) = 2 years

• Rate (r) = 4%

To Find:-

• Principal = ?

Solution:-

The formula used to find Amount is:-

$\sf :\implies Amount = P\bigg(1 + \dfrac{r}{100}\bigg)^{n}$

Substituting the values:-

$\sf \red{\: \: \: \: \: \: \: \: \: \:\:{Amount = P\bigg(1 + \dfrac{r}{100}\bigg)^{n}}}$

$\sf \: \: \: \: \: \: \: \: \: \:\::\implies 1352= P\bigg(1 + \dfrac{4}{100}\bigg)^{2}$

$\sf \: \: \: \: \: \: \: \: \: \:\::\implies 1352= P\bigg( \dfrac{100 + 4}{100}\bigg)^{2}$

$\sf \: \: \: \: \: \: \: \: \: \:\::\implies 1352= P\bigg( \dfrac{104}{100}\bigg)^{2}$

$\sf \: \: \: \: \: \: \: \: \: \:\::\implies 1352= P\bigg( \dfrac{26}{25}\bigg)^{2}$

$\sf \: \: \: \: \: \: \: \: \: \:\::\implies 1352= P\times \dfrac{26 \times 26}{25 \times 25}$

$\sf \: \: \: \: \: \: \: \: \: \:\::\implies 1352= P \times \dfrac{676}{625}$

$\sf \: \: \: \: \: \: \: \: \: \:\::\implies P = 1352\times \dfrac{625}{676}$

$\sf \: \: \: \: \: \: \: \: \: \:\::\implies P = \dfrac{845000}{676}$

$\sf \: \: \: \: \: \: \: \: \:\red{ \:\::\implies P = 1250}$

$\therefore\:\underline{\textsf{ Principle is \textbf{Rs 1250}}}.$