find the slope of this line (2x+3y+4) + λ(6x-y+12) = 0
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Step-by-step explanation:
The two lines are
x(2+6k)+y(3−k)+4+12k=0 ......(1)
and 7x+5y−4=0 ......(2)
Let m
1
and m
2
be the slopes of 1 and 2 respectively. Then,
m
1
=−
3−k
2+6k
,m
2
=−
5
7
If lines 1 and 2 are perpendicular. Then,
m
1
m
2
=−1
(−
3−k
2+6k
)(−
5
7
)=−1
14+42k=−15+5k
k=−
37
29
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