Question

Find the slopes of sides of isosceles triangle ABC whose vertical
LA = 30° and base BC is parallel to x-axis.
A​

Answer 1

Slop of AB = 3.732   &  Slope of AC =  -3.732

Step-by-step explanation:

ABC is isosceles triangle

AB = AC

∠B = ∠C

∠A = 30°

∠A + ∠B + ∠C = 180°

=> 30°  + ∠B + ∠C = 180°

=> ∠B + ∠C = 150°

∠B = ∠C  = 75°

Slop of AB = Tan75°   & Slope of AC = Tan (180 - 75)° = Tan105°

=> Slop of AB = 3.732

Slope of AC =  -3.732

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