Find the slopes of sides of isosceles triangle ABC whose vertical
LA = 30° and base BC is parallel to x-axis.
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Slop of AB = 3.732 & Slope of AC = -3.732
Step-by-step explanation:
ABC is isosceles triangle
AB = AC
∠B = ∠C
∠A = 30°
∠A + ∠B + ∠C = 180°
=> 30° + ∠B + ∠C = 180°
=> ∠B + ∠C = 150°
∠B = ∠C = 75°
Slop of AB = Tan75° & Slope of AC = Tan (180 - 75)° = Tan105°
=> Slop of AB = 3.732
Slope of AC = -3.732
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