Question

Find the sloution x^3+y^3
​

Answer 1

given

X/y = 3/4

so

X = 3y/4

Now

(x^2y +xy^2)/(x^3 + y^3)

putting the value of x

(9y^3/16+ 3y^3/4)/{(27y^3+64y^3)/64}

(21y^3/16)/(91y^3/64)

21*64/91*16

12/13

Option A

Answer 2

Answer:

x/y=3/4

hey mate here is your answer

x^2y+xy:x^3+y^3.

9y^3+3y^3/4. (I)

21y^3/16

21x64

= 27y^3+6y^3/64 (ii)

91y^3/64

=91 x 16

ans 12/13