Find the smallest 4-digit number which is divisible by 6, 8,9
b. 2160
a. 2012
d. 2016
c. 2088
Answers
Answer:
2016
Step-by-step explanation:
from the above options,
a) 2012
it is Divisible by only 6 because as per divisibility rule of 6,every number divisible by 6 must
satisfies the divisibility rule of 2 and 3
b) 2160
it is divisible by 6,9,8 because they satisfies their
divisibility rule
2160=2+1+6+0=9 which satisfies the divisibility rule of 9&3
160=8x20 which satisfies the divisibility rule of 8
2160-0 which satisfies the divisibility rule of 2
c) 2088
it also divisible by 8,6,9
2088=2+0+8+8=18 which satisfies the divisibility
rule of 9&3
2088-8 which satisfies the divisibility rule of 2
88-8x11 which satisfies the divisibility rule of 8
d) 2016
it is also divisible by 6,8,9
2016=2+0+1+6=9which satisfies the divisibility rule of 9&3
2016-6 which satisfies the divisibility rule of 2
16=8x2 which satisfies the divisibility rule of 8
from the above options,
2160,2088,2016 are divisible by 6,8,9 but we need smallest among them. so, answer is 2016
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6 8 9
2016÷6
2016÷8
2016÷9
Answer is
2016
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