Math, asked by sunitasg122, 8 months ago

Find the smallest 4-digit number which is divisible by 6, 8,9
b. 2160
a. 2012
d. 2016
c. 2088​

Answers

Answered by 1805060449
0

Answer:

2016

Step-by-step explanation:

from the above options,

a) 2012

it is Divisible by only 6 because as per divisibility rule of 6,every number divisible by 6 must

satisfies the divisibility rule of 2 and 3

b) 2160

it is divisible by 6,9,8 because they satisfies their

divisibility rule

2160=2+1+6+0=9 which satisfies the divisibility rule of 9&3

160=8x20 which satisfies the divisibility rule of 8

2160-0 which satisfies the divisibility rule of 2

c) 2088

it also divisible by 8,6,9

2088=2+0+8+8=18 which satisfies the divisibility

rule of 9&3

2088-8 which satisfies the divisibility rule of 2

88-8x11 which satisfies the divisibility rule of 8

d) 2016

it is also divisible by 6,8,9

2016=2+0+1+6=9which satisfies the divisibility rule of 9&3

2016-6 which satisfies the divisibility rule of 2

16=8x2 which satisfies the divisibility rule of 8

from the above options,

2160,2088,2016 are divisible by 6,8,9 but we need smallest among them. so, answer is 2016

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Answered by sandipthete3
5

6 8 9

2016÷6

2016÷8

2016÷9

Answer is

2016

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