find the smallest 5 digit no that is exactly divisible by 210 and 315
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Answered by
0
heya guys...
ur answer there
210 = 21*10 = 3*7*2*5. 315 = 5*63 = 5*3*21 = 5*3*3*7. The smallest positive number divisible by both is 2*3*3*5*7 = 630. The smallest positive 5-digit number divisible by both is 10,080.
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CHEERS
ur answer there
210 = 21*10 = 3*7*2*5. 315 = 5*63 = 5*3*21 = 5*3*3*7. The smallest positive number divisible by both is 2*3*3*5*7 = 630. The smallest positive 5-digit number divisible by both is 10,080.
hopes it will help u
thanks
CHEERS
binodsharma:
how can u say that 10.080 is divisible by 630
ya u can check
ha dat is only how to check it dat it is 10 ,080 only
ya
wat ya
u can divide
see my Answer is that helpful
ya ur answer is better
see himanshu answer
Answered by
6
hey . there !!
Start with prime factorizations:
210=2⋅3⋅5⋅7,
and
315=3²⋅5⋅7
This tells us that the two numbers have the factors of 3, 5, and 7 in common, so their LCM must be 2⋅3²⋅5⋅7=630 .
The smallest 5-digit multiple of 630 is
630. 10⁴/630 = 10,080
hope it helps !!
@ himanshu jha
Start with prime factorizations:
210=2⋅3⋅5⋅7,
and
315=3²⋅5⋅7
This tells us that the two numbers have the factors of 3, 5, and 7 in common, so their LCM must be 2⋅3²⋅5⋅7=630 .
The smallest 5-digit multiple of 630 is
630. 10⁴/630 = 10,080
hope it helps !!
@ himanshu jha
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