Question

find the smallest 5 digit no which is exactly divisible by 24 ,36 and 48​

Answer 1

Answer:

yoyoyoyoyoyoyyoyoyoyoyoyoyoy

Answer 2

Step-by-step explanation:

smallest no of 5 digits=10000

any no which has to be divisible by 24 ,36 and 48

has to be a common multiple of these

so, LCM(24 ,36 and 48)= 288

10000 is not divisible by 288

so the required no should be greater than 10000

on dividing 10000 by 288 ......we get

quotient=34

remainder=208

so the required no is 288×35=10080