Question

Find the smallest 5 digit number which is exactly divisible by 32,40 and 56. ​

Answer 1

Answer:

First we have to find the LCM of 8,20 and 24

∴ LCM of given numbers =2×2××2×3×5=120

Greatest number of 3 digit is 999

We divide 999 by 120 and find the remainder

According to given condition , we need a greatest 3-digit number which is exactly divisible by 120

∴ The required number =999−39=960