Find the smallest 6 digit no. which is exactly divisible by 32, 56 and 80
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Find the LCM of
32 = 2x2x2x2x2
56 = 2x2x2x7
80 = 2x2x2x2x5
LCM = 2x2x2x2x2x5x7 = 1120
smallest 6 digit no. =100000
dividing 100000 by 1120 = 89.29
=90 approx.
multiplying 90 by 1120 = 100800.
So 100,800 is the smallest 6-digit number divisible by 32, 56 and 80.
hope it helps.......
if it helps then please mark it as a brainliest answer...
32 = 2x2x2x2x2
56 = 2x2x2x7
80 = 2x2x2x2x5
LCM = 2x2x2x2x2x5x7 = 1120
smallest 6 digit no. =100000
dividing 100000 by 1120 = 89.29
=90 approx.
multiplying 90 by 1120 = 100800.
So 100,800 is the smallest 6-digit number divisible by 32, 56 and 80.
hope it helps.......
if it helps then please mark it as a brainliest answer...
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Step-by-step explanation:
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