Question

Find the smallest 6 digit no. which is exactly divisible by 32, 56 and 80

Answer 1

Find the LCM of

32 = 2x2x2x2x2

56 = 2x2x2x7

80 = 2x2x2x2x5

LCM = 2x2x2x2x2x5x7 = 1120

smallest 6 digit no. =100000

dividing 100000 by 1120 = 89.29
=90 approx.


multiplying 90 by 1120 = 100800.

So 100,800 is the smallest 6-digit number divisible by 32, 56 and 80.

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Answer 2

Step-by-step explanation:

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