Math, asked by AdishAnil, 10 months ago

Find the smallest four digit number which is divisible by 18 , 24 and 32

i will mark the best answer as brainliest

Answers

Answered by chandni164
1

HEY MATE!

The smallest 4 digit number which is divisible by 18, 24, and 32 is 1152.

EXPLANATION: The LCM of 18 ,32 ,and 24 is 288.

The smallest 4 digit number should necessarily be the multiple of 288.

so we have to find the smallest 4 digit number divisible by 288.

Therefore, 288×1=288

288×2=576

288×3=864

288×4=1152

That means 1152 is the smallest 4 digit number divisible by 288.

As 288 is divisible by 18, 24, and 32 , 1152 becomes the smallest 4 digit number divisible by 18 , 24 , and 32.

HOPE IT HELPS!

IF ANY DOUBTS PLS DO ASK!

PLS MARK AS BRAINLIEST!❤❤

Answered by Anonymous
0

ANSWER:-------

Four digit no. = )

{Since 288 is divisible by 18, 24 and 32, 1152 is also divisible by all these numbers.}

{Therefore,1152 is the smallest four digit number divisible by 18, 24 and 32.}

hope it helps:------

pls mark as brain list

T!—!ANKS!!!

Similar questions