find the smallest integer n so that 5×12×n is the product of three consecutive integers
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Answered by
85
This type of questions , you can solve by Hit and trail method' .
given , 5 × 12 × n = 60n
question said " smallest integer value of n so that 60n is the product of three consecutive integers.
Let n = 1 then, 60 × 1 = 60
Let's try to break it ,
60 = 2 × 2 × 3 × 5 = 3 × 4 × 5
What you see, 60 is the product of three consecutive integers 3, 4, 5
Hence, smallest integer value of n is 1.
given , 5 × 12 × n = 60n
question said " smallest integer value of n so that 60n is the product of three consecutive integers.
Let n = 1 then, 60 × 1 = 60
Let's try to break it ,
60 = 2 × 2 × 3 × 5 = 3 × 4 × 5
What you see, 60 is the product of three consecutive integers 3, 4, 5
Hence, smallest integer value of n is 1.
hanshika5:
thank you
Answered by
60
Hi ,
5 × 12 × n = 60n
If n = 1 ,
5 × 12 × 1 = 60
= 3 × 4 × 5 ( product of consecutive integers )
required smallest integer n = 1
I hope this helps you .
: )
5 × 12 × n = 60n
If n = 1 ,
5 × 12 × 1 = 60
= 3 × 4 × 5 ( product of consecutive integers )
required smallest integer n = 1
I hope this helps you .
: )
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