Question

find the smallest natural number by which 363 should be divided so get a perfect square

Answer 1

363 = 3×121 = 3× 11× 11



now square of 363


$= \sqrt{363} \\ \\ = \sqrt{3 \times 11 \times 11} \\ \\ = \sqrt{3 \times {11}^{2} } \\ \\ = \sqrt{3} \times 11$



here we can see the pair of 11 but 3 is left so the number will be 3
as

$363 \div 3 = 121$


and 121 is a perfect square of 11

Answer 2

Step-by-step explanation:

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