Math, asked by gopikv1517, 4 days ago

Find the smallest natural number given below when divided by 3, 4 and 5 gives the remainder 1. (A) 71 (B) 51 (C) 41 (D) 61

Answers

Answered by nitishkumarsoy

3

Answer:

61

Step-by-step explanation

LCM of 3,4,5 is 60.

So 61 is smallest natural number when divided by 3,4,5 gives remainder 1.

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