Question

find the smallest natural number which when divided by 15,20,25 and 45 leaves reminder as 8 in each case​

Answer 1

Answer:

According to the question, the remainder should be 8, So we'll add 8 to 900 that is answer is 908.

Answer 2

The two positive integer numbers, a and b satisfy that a(a-b) = 23. What is b?

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The two positive integer numbers, a and b satisfy that a(a-b) = 23. What is b?

a(a-b)=23

So, a or b has to be 1. Following up on that

Let a = 1

1 - b = 23

- b = 23 - 1

b = - 22 (rejected, a and b both has to be positive as per question)

Now let, (a - b) = 1, so a has to be 23

because

23(a-b)=23*1 = 23

So, then we should have

a - b = 1

or, 23 - b = 1

or, b = 23 - 1

or, b = 22

This is indeed the answer, a and b are both positive in this case, as required