find the smallest natural number which when divided by 16,24and 40 leaves the remainder 8 in each case
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Answer:
248
Step-by-step explanation:
248 is the smallest number which when divided by 16, 24 and 40 leaves the remainder.
Answered by
1
Answer:
248 is the smallest natural number which when divided by 16,24 and 40 leaves remainder 8 in each case
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