Math, asked by joanj2oos, 1 year ago

Find the smallest natural number which when divided by 16, 24, 40 leaves a remainder 8 in each case

Answers

Answered by cuteipie82

17

16-8,24-8,40-8
8,16,32
8=2*2*2
16=2*2*2*2
32=2*2*2*2*2
HCF=2*2*2=>8

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