Question

find the smallest no.by which 243 must be divided to get a perfect cube.Also find the cuberoot of the cube so obtained​

Answer 1

Answer:

Step-by-step explanation:

We have 243 = 3 × 3 × 3 × 3 ×3

The prime factor 3 is not a group of three.    

∴ 243 is not a perfect cube.                

Now, [243] × 3 = [3 × 3 × 3 × 3 × 3] × 3                  

or 729 =3 × 3 × 3 × 3 × 3 × 3                  

Now, 729 becomes a perfect cube.                  

Thus, the smallest required number to multiply 243 to make it a perfect cube is 3.

The cube root of 729 is 9.

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Answer 2

Answer:

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