Question

find the smallest no such that when divided by 28,38 and 48 leaves remainder 18,28 and 38
​

Answer 1

Answer:

10 is the smallest no. which divide 28,28and 48 leaves remainder 18,28,and 38

Answer 2

Answer:

first we have to subtract

28-18=10

38-28=10and

48-38=10

now we have to find the LCM of

10,10,10i.e.,10

Therefore, the smallest number is 10.